So there's a rope.... if you put a weight on the end of it, the rope may snap. In order to figure out if it would snap, and which side of the rope would cause it to snap, we have to use these things... they're kinda like labels, but not really. Dang-it why can't I remember?? They're um.. whatchamacallits... VECTORS!!
In order to determine which side is most likely to snap, we have to draw a line, labeled 'F-net up' pointing upward from the ball (the ball is the weight on the end of the rope). Then, we need to draw a line pointing downward from the weight labeled 'F-weight.' Using a ruler, draw a diagonal line using the F-net up arrow as your guide. Line the ruler up with the top of the arrow and draw a line pointing up to the right and then an arrow pointing up to the left (you can see this in the picture). P.s. make sure you label one side, Side 1 and the other Side 2 so that you have a reference point as to which side, if any, would most likely snap. Drawing a line across and up from the middle of the ball and up to the vector lines on both sides, you can see which side would most likely break. The side with the longer vector is the side that will most likely break due to the tension put on the rope. Vector's also help us understand why boxes go down a slope and a sled slides down a hill.
Well, if you want to go skydiving any time soon and receive extra credit in physics, you have to understand... um.... uh... well.. this is awkward.... what's it called? It explains why it is that a diver speeds up so fast for a long time and then eventually begins to have a steady pace. It's called um... whatchamacallit... air resistance!! Air resistance is the forces that are in opposition to the relative motion of an object through the air. There are 2 things that will increase the force of air resistance: Increase the speed and increase the surface area. The force of air resistance increases as a parson falls through the air because they are speeding up. When someone is falling, their acceleration decreases, velocity increases, and the net force decreases. An important rule about air resistance is that acceleration is directly proportional to force. This means that when acceleration decreases, so does the net force and when acceleration increases, so does the net force.
So there's this formula that defines why that if a car and truck crash, the same force is impacted on both vehicles. If only I could remember the dang formula... it's umm... it's... whatchamacallit? f=ma. We know that the mass of a big semi-truck will most likely be bigger than the force of a tiny Toyota Camry. When the truck with a larger mass runs into a tiny car, the truck causes the car to accelerate forwards. This acceleration is obviously greater than the truck's acceleration.
Truck --> f=Ma
Car --> f=mA
Both of these equations will equal out, causing the force to be the same for both vehicles.
So there are two different kinds of velocities. One type is defined by how many rotations it makes in a given amount of time. The other defines the distance it covers in the same amount of time... well... if only I could remember these names for the different velocities. Well, the first one covers rotations.. so that's um... whatchamacallit? Rotational velocity!! Now I just have to figure out the second... this one covers the distance in a given time. It's not rotational so it must be... whatchamacallit? Tangential Velocity!! Lets say there are two cylinders, one large and one small and they are connected by a chain. Since tangential velocity is the distance they cover in an amount of time, the small cylinder has to keep up with the bigger one. Because of this, they have the same tangential velocity. We can figure out which cylinder has a greater rotational velocity by finding out how bug the cylinders are. The smaller wheel has a greater rotational velocity because the smaller one has to spin more times to get to the same distance as the bigger one.
So there's this reason that physics describes as to why and how an athlete doesn't fall over easily. There's one main principle to it and if you aren't doing it, you have a much greater chance of falling over. This is called... um... really? I can't remember it? its.. ugh... whatchamacallit? Base of Support!!! An athlete is less likely to be pushed over when they keep their legs shoulder width apart because having your legs shoulder width apart creates a lower center of gravity which causes stability due to a wider base of support.
There's a formula that describes to us why a car takes a long time to fully stop. If only I could remember what it was... I remember it has 2 initials, a 1/2, a quantity squared... it's whatchamacallit... that's right! KE=1/2mv^2. Let's say a car is moving at some speed and requires 10 m to stop. How many meters will it take to stop if the speed of the car is tripled? We can solve this by just plugging in 3v and then using that information to find work.
KE= 1/2m(3v)^2
KE= 9(1/2mv^2)
Work=change in KE
f(d)=change in KE
f(9d) = 9(KE)
This would take 9 miles.
So there's this thing that helps us understand why a bird isn't harmed when standing on a wire, but they get harmed if they run into both wires on a power line... how is this possible? Something about connecting a... um... what do you call it? We use it everywhere we have electricity... what's it called? um... whatchamacallit... A CIRCUIT!! That's right!! If a bird were to fly through the wires and touch both wires with its wings, the bird would be completing the circuit. When both wings complete the circuit there is a large potential difference so the voltage is increased and this causes the bird to get electrocuted. If the bird just stood or ran into one wire, it would not be completing the circuit so it would be fine.
There are only two more things I have to remember. It's an equation we use to describe why things such as a charged piece of cling wrap is attracted to a ceramic bowl. It's an equation with lots of exponents and looks kinds difficult but as long as you know how to plug in numbers, you're okay! I should be pretty good with figuring out these things by now.... it's um.. whatchamacallit?... oh it's Columb's Law: F=k(q1q2/d^2). When a charged piece of cling wrap gets close to the bowl, the bowl polarizes. Positive charges in the bowl move toward the cling wrap and negative charges move away. The bowl is not charged, it is simply polarized due to the fact that opposite charges attract and like charges repel. Since the distance between the opposite attractive charges is less than the distance between the like, repulsive charges, the attractive force is greater than the repulsive force. This is because of Columb's Law F=k(q1q2/d^2). Because the attractive force is larger, the cling wrap is pulled toward the bowl.
Okay, one more thing. There's this problem I have, I can't figure out the physic's behind why exactly air bags protect us. I mean I know that the air bag is big and fluffy and it's better than smacking your head on a dashboard... but I just can't remember the formula's that go into figuring out why this happens.... this problem is a doozy because it requires 5 equations!! That's a lot to remember, hence my current problem..... I think that if I think hard enough I'll remember all 5 whatchamacallits!! Well, I believe the first equation is p=mv. I can figure out the second one because it's the same as the first: change in p = p(final) - p(initial). Because the change in p is always the same, this means the impulse is also the same. And oh yeah!! Impulse=f(change in p). With these equations, I am able to find out why airbags are so important!!
When a person sometimes has to make a rash decision to slam on their brakes, he or she would like to know that they have the best safety precautions. No matter how they slam on their brakes, they go from moving to not moving. Because of this, change in momentum is always the same.
p=mv
change in p = p(final) - p(initial)
Because the change in p is always the same, so is the impulse.
J=change in p
If a person had to slam on their brakes, they would want to have a small force on their body because the greater the force, the greater the injury. If there were no airbag, They would be stopped very quickly by the dashboard, making the force very large. A driver would prefer to have airbags because it would take longer for the person to stop moving, causing a smaller force.
J=F(change in p)
J=f(CHANGE IN P)















